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13.Nuclei
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The activity of a radioactive material is $2.56 \times 10^{-3} \,Ci$. If the half life of the material is $5$ days, after how many days the activity will become $2 \times 10^{-5} \,Ci$ ?
A
$30$
B
$35$
C
$40$
D
$25$
(JEE MAIN-2022)
Solution
$\frac{ A }{ A _{0}}=\frac{ N }{ N _{0}}$
$\frac{2 \times 10^{-5}}{2.56 \times 10^{-3}}=\frac{ N }{ N _{0}}$
$\frac{ N }{ N _{0}}=\frac{1}{128} \Rightarrow N =\frac{ N _{0}}{128}$
After $7$ half life activity comes down to given value $T =7 \times 5$ $=35$ days
Standard 12
Physics
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