13.Nuclei
medium

The activity of a radioactive material is $2.56 \times 10^{-3} \,Ci$. If the half life of the material is $5$ days, after how many days the activity will become $2 \times 10^{-5} \,Ci$ ?

A

$30$

B

$35$

C

$40$

D

$25$

(JEE MAIN-2022)

Solution

$\frac{ A }{ A _{0}}=\frac{ N }{ N _{0}}$

$\frac{2 \times 10^{-5}}{2.56 \times 10^{-3}}=\frac{ N }{ N _{0}}$

$\frac{ N }{ N _{0}}=\frac{1}{128} \Rightarrow N =\frac{ N _{0}}{128}$

After $7$ half life activity comes down to given value $T =7 \times 5$ $=35$ days

Standard 12
Physics

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