For a radioactive material, half-life is 10 m | vedclass

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Question

Number of nuclei remaining,

$N=600-450=150$

According to the law of radioactive decay,

$\frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{\frac{t}{T_

Vedclass · Accepted Answer

$20$

Vedclass · Answer

Number of nuclei remaining,

$N=600-450=150$

According to the law of radioactive decay,

$\frac{N}{N_{0}}=\left(\frac{1}{2}ight)^{\frac{t}{T_{1 / 2}}} ;$ where $N_{0}$ is the number of nuclei initially.

$	herefore \quad \frac{150}{600}=\left(\frac{1}{2}ight)^{\frac{t}{T_{1 / 2}}} ;$ where $T_{1 / 2}=$ half life.

or $\quad\left(\frac{1}{2}ight)^{2}=\left(\frac{1}{2}ight)^{\frac{t}{T_{1 / 2}}}$

$\Rightarrow t=2 T_{10}=2 	imes 10$ minutes $=20$ minutes

For a radioactive material, half-life is $10$ minutes. If initially there are $600$ number of nuclei, the time taken (in minutes) for the disintegration of $450$ nuclei is

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