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The amount of heat produced in an electric circuit depends upon the current $(I),$ resistance $(R)$ and time $(t).$ If the error made in the measurements of the above quantities are $2\%, 1\%$ and $1\%$ respectively then the maximum possible error in the total heat produced will be ........... $\%$
$1$
$2$
$6$
$3$
Solution
$\begin{array}{l}
Give\,:\,\frac{{\Delta I}}{I} \times 100 = 2\% ;\\
\frac{{\Delta R}}{R} \times 100 = 1\% \,and\,\frac{{\Delta t}}{t} \times 100 = 1\% \\
Heat\,produced,\,H = {I^2}Rt\\
Maximum\,possible\,error\,in\,heat\,produced,\\
= \frac{{\Delta H}}{H} \times 100\\
= 2\left( {\frac{{\Delta I}}{I} \times 100} \right) + \frac{{\Delta R}}{R} \times 100 + \frac{{\Delta t}}{t} \times 100\\
= 2 \times 2\% + 1\% + 1\% = 6\%
\end{array}$