Gujarati
13.Nuclei
easy

The average life $T$ and the decay constant $\lambda $ of a radioactive nucleus are related as

A

$T\lambda = 1$

B

$T = \frac{{0.693}}{\lambda }$

C

$\frac{T}{\lambda } = 1$

D

$T = \frac{C}{\lambda }$

Solution

(a) Average life $T = \frac{{{\rm{The\, sum\, of\, all \,the \,lives \,of \,all\, atoms}}}}{{{\rm{Total\, number\, of\, atoms}}}} $

$= \frac{1}{\lambda }$

==> $ T \lambda = 1$

Standard 12
Physics

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