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13.Nuclei
easy
The average life $T$ and the decay constant $\lambda $ of a radioactive nucleus are related as
A
$T\lambda = 1$
B
$T = \frac{{0.693}}{\lambda }$
C
$\frac{T}{\lambda } = 1$
D
$T = \frac{C}{\lambda }$
Solution
(a) Average life $T = \frac{{{\rm{The\, sum\, of\, all \,the \,lives \,of \,all\, atoms}}}}{{{\rm{Total\, number\, of\, atoms}}}} $
$= \frac{1}{\lambda }$
==> $ T \lambda = 1$
Standard 12
Physics
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