બુલિયન સમીકરણ (mathrm{p} wedge mathrm{q}) Rig | vedclass

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Question

$(p \wedge q) \Rightarrow((r \wedge q) \wedge p)$

$\sim(p \wedge q) \vee((r \wedge q) \wedge p)$

$\sim(p \wedge q) \vee((r \wedge p) \wedge(p \w

Vedclass · Accepted Answer

$(\mathrm{p} \wedge \mathrm{q}) \Rightarrow(\mathrm{r} \wedge \mathrm{p})$

Vedclass · Answer

$(p \wedge q) \Rightarrow((r \wedge q) \wedge p)$

$\sim(p \wedge q) \vee((r \wedge q) \wedge p)$

$\sim(p \wedge q) \vee((r \wedge p) \wedge(p \wedge q)$

$\Rightarrow[\sim(p \wedge q) \vee(p \wedge q)] \wedge(\sim(p \wedge q) \vee(r \wedge p))$

$\Rightarrow t \wedge[\sim(p \wedge q) \vee(r \wedge p)]$

$\Rightarrow \sim(p \wedge q) \vee(r \wedge p)$

$\Rightarrow(p \wedge q) \Rightarrow(r \wedge p)$

Aliter:

given statement says

" if $\mathrm{p}$ and $\mathrm{q}$ both happen then

$\mathrm{p}$ and $\mathrm{q}$ and $\mathrm{r}$ will happen"

it Simply implies

"If $\mathrm{p}$ and $\mathrm{q}$ both happen then

'r' too will happen "

i.e.

" if $\mathrm{p}$ and $\mathrm{q}$ both happen then $\mathrm{r}$ and $\mathrm{p}$ too will happen

i.e.

$(p \wedge q) \Rightarrow(r \wedge p)$

બુલિયન સમીકરણ $(\mathrm{p} \wedge \mathrm{q}) \Rightarrow((\mathrm{r} \wedge \mathrm{q}) \wedge \mathrm{p})$ એ . . . ને તુલ્ય છે.

Similar Questions

$ \sim s \vee \left( { \sim r \wedge s} \right)$ નું નિષેધ . . . . . . . ને સમાનાર્થી છે.

નીચેના પૈકી કયું અસત્ય છે ?

વિધાન $\sim p \wedge(p \vee q)$ નું નિષેધ ...... છે.

બુલીયન બહુપદી $\left( {p\;\wedge \sim q} \right)\;\;\vee \;q\;\;\vee \left( { \sim p\wedge q} \right)$ એ . . . . સમાનાર્થી છે. .

$p \Leftrightarrow q$ =