2. Electric Potential and Capacitance
easy

$4 \times {10^{ - 6}}$ ફેરાડે કેપેસીટન્સ ધરાવતા કેપેસીટરને $100\,\,volts$ થી ચાર્જ કરવામાં આવે તો સંગ્રહાતી ઉર્જા .......$Joule$ થાય 

A

$0.02$

B

$0.04$

C

$0.025$

D

$0.05$

(AIIMS-1980) (AIIMS-1984)

Solution

(a) $U = \frac{1}{2}C{V^2} = \frac{1}{2} \times 4 \times {10^{ – 6}} \times {(100)^2} = 0.02\,J$

Standard 12
Physics

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