Gujarati
10-1.Circle and System of Circles
medium

The circle on the chord $x\cos \alpha + y\sin \alpha = p$ of the circle ${x^2} + {y^2} = {a^2}$ as diameter has the equation

A

${x^2} + {y^2} - {a^2} - 2p(x\cos \alpha + y\sin \alpha - p) = 0$

B

${x^2} + {y^2} + {a^2} + 2p(x\cos \alpha - y\sin \alpha + p) = 0$

C

${x^2} + {y^2} - {a^2} + 2p(x\cos \alpha + y\sin \alpha + p) = 0$

D

${x^2} + {y^2} - {a^2} - 2p(x\cos \alpha - y\sin \alpha - p) = 0$

Solution

(a) Get combined equation of family of circles through points of intersection of line and circle and then apply condition for radius of circle.

Standard 11
Mathematics

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