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7.Binomial Theorem
hard
The coefficient of $x^{7}$ in the expression $(1+x)^{10}+x(1+x)^{9}+x^{2}(1+x)^{8}+\ldots+x^{10}$ is
A
$120$
B
$330$
C
$210$
D
$420$
(JEE MAIN-2020)
Solution
Coefficient of $x^{7}$ is
$^{10} \mathrm{C}_{7}+^{9} \mathrm{C}_{6}+^{5} \mathrm{C}_{5}+\ldots+^{4} \mathrm{C}_{1}+^{3} \mathrm{C}_{0}$
$\underbrace{^{4} C_{0}+^{4} C_{1}}_{^{5} C_{1}}+^{5} C_{2}+\ldots+^{10} C_{7}=^{11} C_{7}=330$
Standard 11
Mathematics