7.Binomial Theorem
hard

સમીકરણ $(1+x)^{10}+x(1+x)^{9}+x^{2}(1+x)^{8}+\ldots+x^{10}$ માં $x^{7}$ નો સહગુણક મેળવો.

A

$120$

B

$330$

C

$210$

D

$420$

(JEE MAIN-2020)

Solution

Coefficient of $x^{7}$ is

$^{10} \mathrm{C}_{7}+^{9} \mathrm{C}_{6}+^{5} \mathrm{C}_{5}+\ldots+^{4} \mathrm{C}_{1}+^{3} \mathrm{C}_{0}$

$\underbrace{^{4} C_{0}+^{4} C_{1}}_{^{5} C_{1}}+^{5} C_{2}+\ldots+^{10} C_{7}=^{11} C_{7}=330$

Standard 11
Mathematics

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