The coefficient of apparent expansion of merc | vedclass

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Question

The real expansion is given as the sum of apparent expansion and the vessel expansion.

$\gamma_{	ext {real}}=\gamma_{	ext {app}}+\gamma_{	ext {v

Vedclass · Accepted Answer

$9 	imes 10^{-6} /{ }^{\circ} C$

Vedclass · Answer

The real expansion is given as the sum of apparent expansion and the vessel expansion.

$\gamma_{	ext {real}}=\gamma_{	ext {app}}+\gamma_{	ext {vessel}}$

$	herefore\left(\gamma_{	ext {app}}+\gamma_{	ext {vessel}}ight)_{	ext {glass }}=\left(\gamma_{	ext {app}}+\gamma_{	ext {vessel}}ight)_{	ext {stee }}$

$153 	imes 10^{-6}+\left(\gamma_{	ext {vessel}}ight)_{	ext {glass }}=144 	imes 10^{-6}+\left(\gamma_{	ext {vessel}}ight)_{	ext {steel }}$

$\left(\gamma_{	ext {vessel}}ight)_{	ext {steel }}=3 \alpha=3 	imes 12 	imes 10^{-6}=36 	imes 10^{-6} /{ }^{\circ} C$

The expansion of glass comes out be,

$153 	imes 10^{-6}+\left(\gamma_{	ext {vessel}}ight)_{	ext {glass }}=144 	imes 10^{-6}+36 	imes 10^{-6}$

$\left(\gamma_{	ext {vessel}}ight)_{	ext {glass }}=3 \alpha=27 	imes 10^{-6} /{ }^{\circ} C$

$\alpha=9 	imes 10^{-6} /{ }^{\circ} C$

The coefficient of apparent expansion of mercury in a glass vessel is $153 \times 10^{-6} /{ }^{\circ} C$ and in steel vessel is $144 \times 10^{-6} /{ }^{\circ} C$. If $\alpha$ for steel is $12 \times 10^{-6} /{ }^{\circ} C ,$ then that of glass is

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