3-1.Vectors
medium

સદિશ $ A = 2\hat i + 3\hat j $ નો સદિશ $ \hat i + \hat j $ ની દિશામાંનો ઘટક

A

$ \frac{5}{{\sqrt 2 }} $

B

$ 10\sqrt 2 $

C

$ 5\sqrt 2 $

D

$ 5 $

Solution

(a)$\frac{{\overrightarrow A .\overrightarrow B }}{{|\vec i + \vec j|}} = \frac{{(2\hat i + 3\hat j)\,(\hat i + \hat j)}}{{\sqrt 2 }}$$ = \frac{{2 + 3}}{{\sqrt 2 }} = \frac{5}{{\sqrt 2 }}$

Standard 11
Physics

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