- Home
- Standard 12
- Physics
13.Nuclei
medium
The disintegration rate of a certain radioactive sample at any instant is $4250$ disintegrations per minute.$10$ minutes later, the rate becomes $2250$ disintegrations per minute. The approximate decay cons $.........\min^{-1}$
A
$0.02$
B
$2.7$
C
$0.063$
D
$6.3$
(JEE MAIN-2022)
Solution
At $t=0$ disintegration rate $=4250\,dpm$
At $t=10$ disintegration rate $=2250\,dpm$
$A=A_{0} e^{-\lambda t}$
$2250=4250\,e ^{-\lambda .(10)}$
$\Rightarrow \lambda(10)=\ln \left(\frac{4250}{2250}\right)$
$\Rightarrow \lambda=0.063 min ^{-1}$
Standard 12
Physics
Similar Questions
hard