13.Nuclei
medium

The disintegration rate of a certain radioactive sample at any instant is $4250$ disintegrations per minute.$10$ minutes later, the rate becomes $2250$ disintegrations per minute. The approximate decay cons $.........\min^{-1}$

A

$0.02$

B

$2.7$

C

$0.063$

D

$6.3$

(JEE MAIN-2022)

Solution

At $t=0$ disintegration rate $=4250\,dpm$

At $t=10$ disintegration rate $=2250\,dpm$

$A=A_{0} e^{-\lambda t}$

$2250=4250\,e ^{-\lambda .(10)}$

$\Rightarrow \lambda(10)=\ln \left(\frac{4250}{2250}\right)$

$\Rightarrow \lambda=0.063 min ^{-1}$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.