The distance $s$ travelled by a particle in time $t$ is $s=u t-\frac{1}{2} \,g t^{2}$. The initial velocity of the particle was measured to be $u=1.11 \pm 0.01 \,m / s$ and the time interval of the experiment was $t=1.01 \pm 0.1 \,s$. The acceleration was taken to be $g=9.8 \pm 0.1 \,m / s ^{2}$. With these measurements, the student estimates the total distance travelled. How should the student report the result?

A student measures the time period of $100$ oscillations of a simple pendulum four times. The data set is  $90\;s$ ,$91\;s $, $95\;s$ and $92\;s$. If the minimum division in the  measuring clock is $1\;s$, then the reported mean time should be

Three students $S_{1}, S_{2}$ and $S_{3}$ perform an experiment for determining the acceleration due to gravity $(g)$ using a simple pendulum. They use different lengths of pendulum and record time for different number of oscillations. The observations are as shown in the table.

(Least count of length $=0.1 \,{m}$, least count for time $=0.1\, {s}$ )

If $E_{1}, E_{2}$ and $E_{3}$ are the percentage errors in $'g'$ for students $1,2$ and $3$ respectively, then the minimum percentage error is obtained by student no. ....... .

In an experiment, mass of an object is measured by applying a known force on it, and then measuring its acceleration. If in the experiment, the measured values of applied force and the measured acceleration are $F=10.0 \pm 0.2 \,N$ and $a=1.00 \pm 0.01 \,m / s ^2$, respectively. Then, the mass of the object is ............... $kg$

If radius of the sphere is $(5.3 \pm 0.1)\;cm$. Then percentage error in its volume will be

The percentage error in the measurement of $g$ is $.....\%$ (Given that $g =\frac{4 \pi^2 L }{ T ^2}, L =(10 \pm 0.1)\,cm$, $T =(100 \pm 1)\,s )$