A student measures the time period of $100$ oscillations of a simple pendulum four times. The data set is $90\;s$ ,$91\;s $, $95\;s$ and $92\;s$. If the minimum division in the measuring clock is $1\;s$, then the reported mean time should be
$92\pm 2\;s$
$92\pm 3\;s$
$92\pm 1.8\;s$
$92\pm 5\;s$
The maximum percentage errors in the measurement of mass (M), radius (R) and angular velocity $(\omega)$ of a ring are $2 \%, 1 \%$ and $1 \%$ respectively, then find the maximum percenta? error in the measurement of its moment of inertia $\left(I=\frac{1}{2} M R^{2}\right)$ about its geometric axis.
A physical quantity $y$ is represented by the formula $y=m^{2}\, r^{-4}\, g^{x}\,l^{-\frac{3}{2}}$. If the percentage error found in $y, m, r, l$ and $g$ are $18,1,0.5,4$ and $p$ respectively, then find the value of $x$ and $p$.
The distance $s$ travelled by a particle in time $t$ is $s=u t-\frac{1}{2} \,g t^{2}$. The initial velocity of the particle was measured to be $u=1.11 \pm 0.01 \,m / s$ and the time interval of the experiment was $t=1.01 \pm 0.1 \,s$. The acceleration was taken to be $g=9.8 \pm 0.1 \,m / s ^{2}$. With these measurements, the student estimates the total distance travelled. How should the student report the result?
We measure the period of oscillation of a simple pendulum. In successive measurements, the readings turn out to be $2.63 \;s , 2.56 \;s , 2.42\; s , 2.71 \;s$ and $2.80 \;s$. Calculate the absolute errors, relative error or percentage error.
A physical quantity is $A = P^2/Q^3.$ The percentage error in measurement of $P$ and $Q$ is $x$ and $y$ respectively. Maximum error in measurement of $A$ is