The eccentricity of the ellipse 4{x^2} + 9{y^ | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(d) $4{x^2} + 8x + 4 + 9{y^2} + 36y + 36 = 36$

$ \Rightarrow \frac{{{{(x + 1)}^2}}}{9} + \frac{{{{(y + 2)}^2}}}{4} = 1$;

$e = \sqrt {1 - \frac{4

Vedclass · Accepted Answer

$\frac{{\sqrt 5 }}{3}$

Vedclass · Answer

(d) $4{x^2} + 8x + 4 + 9{y^2} + 36y + 36 = 36$

$ \Rightarrow \frac{{{{(x + 1)}^2}}}{9} + \frac{{{{(y + 2)}^2}}}{4} = 1$;

$e = \sqrt {1 - \frac{4}{9}} = \frac{{\sqrt 5 }}{3}$.

The eccentricity of the ellipse $4{x^2} + 9{y^2} + 8x + 36y + 4 = 0$ is

Similar Questions

On the ellipse $4{x^2} + 9{y^2} = 1$, the points at which the tangents are parallel to the line $8x = 9y$ are

If the normal to the ellipse $3x^2 + 4y^2 = 12$ at a point $P$ on it is parallel to the line, $2x + y = 4$ and the tangent to the ellipse at $P$ passes through $Q(4, 4)$ then $PQ$ is equal to

For the ellipse $3{x^2} + 4{y^2} = 12$, the length of latus rectum is

A man running a racecourse notes that the sum of the distances from the two flag posts from him is always $10 \,m$ and the distance between the flag posts is $8\, m$ Find the equation of the posts traced by the man.

Eccentric angle of a point on the ellipse ${x^2} + 3{y^2} = 6$ at a distance $2$ units from the centre of the ellipse is