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10-2. Parabola, Ellipse, Hyperbola
medium
The eccentricity of the ellipse $4{x^2} + 9{y^2} + 8x + 36y + 4 = 0$ is
A
$\frac{5}{6}$
B
$\frac{3}{5}$
C
$\frac{{\sqrt 2 }}{3}$
D
$\frac{{\sqrt 5 }}{3}$
Solution
(d) $4{x^2} + 8x + 4 + 9{y^2} + 36y + 36 = 36$
$ \Rightarrow \frac{{{{(x + 1)}^2}}}{9} + \frac{{{{(y + 2)}^2}}}{4} = 1$;
$e = \sqrt {1 – \frac{4}{9}} = \frac{{\sqrt 5 }}{3}$.
Standard 11
Mathematics