Gujarati
10-2. Parabola, Ellipse, Hyperbola
easy

The eccentricity of the hyperbola ${x^2} - {y^2} = 25$ is

A

$\sqrt 2 $

B

$1/\sqrt 2 $

C

$2$

D

$1 + \sqrt 2 $

Solution

(a) $\frac{{{x^2}}}{{25}} – \frac{{{y^2}}}{{25}} = 1$.

Eccentricity $ = \sqrt 2 $ as $a = b$.

Standard 11
Mathematics

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