Gujarati
10-2. Parabola, Ellipse, Hyperbola
easy

अतिपरवलय $2{x^2} - {y^2} = 6$ की उत्केन्द्रता है

A

$\sqrt 2 $

B

$2$

C

$3$

D

$\sqrt 3 $

Solution

(d) $\frac{{{x^2}}}{{(6/2)}} – \frac{{{y^2}}}{6} = 1$

$⇒ {a^2} = 3$ व ${b^2} = 6$

इसलिए $e = \sqrt {\frac{{{b^2}}}{{{a^2}}} + 1} $

$⇒ e = \sqrt 3 $.

Standard 11
Mathematics

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