Gujarati
10-2. Parabola, Ellipse, Hyperbola
medium

अतिपरवलय $5{x^2} - 4{y^2} + 20x + 8y = 4$ की उत्केन्द्रता है

A

$\sqrt 2 $

B

$\frac{3}{2}$

C

$2$

D

$3$

Solution

(b) परवलय का दिया गया समीकरण

$5{x^2} – 4{y^2} + 20x + 8y = 4$ है

$5{(x + 2)^2} – 4\,{(y – 1)^2} = 20$ 

$⇒ \frac{{{{(x + 2)}^2}}}{4} – \frac{{{{(y – 1)}^2}}}{5} = 1$

${b^2} = {a^2}({e^2} – 1)$ से $5 = 4({e^2} – 1)$

$ \Rightarrow {e^2} = 9/4$

$\Rightarrow e = 3/2$.

Standard 11
Mathematics

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