11.Thermodynamics
normal

The efficiency of a Carnot's engine, working between steam point and ice point, will be  $....\,\%$

A

$26.81$

B

$37.81$

C

$47.81$

D

$57.81$

Solution

$\eta=\left[1-\frac{ T _{ L }}{ T _{ n }}\right] \times 100 \,\%$

$T _{ L }=0{ }^{\circ} C =273 \,K , T _{ n }=373\, K$

$\therefore \eta=26.809\, \%$

Standard 11
Physics

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