સમીકરણ sqrt {(x + 1)} - sqrt {(x - 1)} = sqrt | vedclass

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Question

(d) Given $\sqrt {(x + 1)} - \sqrt {(x - 1)} = \sqrt {(4x - 1)} $.....$(i)$

Squaring both sides, we get, $ - 2\sqrt {({x^2} - 1)} = 2x - 1$

Squa

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(d) Given $\sqrt {(x + 1)} - \sqrt {(x - 1)} = \sqrt {(4x - 1)} $.....$(i)$

Squaring both sides, we get, $ - 2\sqrt {({x^2} - 1)} = 2x - 1$

Squaring again, we get, $x = {5 \over 4},$ which does not satisfy eq. $(i).$

Hence, there is no solution of the given equation.

સમીકરણ $\sqrt {(x + 1)} - \sqrt {(x - 1)} = \sqrt {(4x - 1)} $, $x \in R$ ને .. . .

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