The equation of ellipse whose distance between the foci is equal to $8$ and distance between the directrix is $18$, is
$5{x^2} - 9{y^2} = 180$
$9{x^2} + 5{y^2} = 180$
${x^2} + 9{y^2} = 180$
$5{x^2} + 9{y^2} = 180$
The eccentricity of the ellipse $ (x - 3)^2 + (y - 4)^2 =$ $\frac{{{y^2}}}{9}\,$ is
The position of the point $(1, 3)$ with respect to the ellipse $4{x^2} + 9{y^2} - 16x - 54y + 61 = 0$
An ellipse having foci at $(3, 3) $ and $(- 4, 4)$ and passing through the origin has eccentricity equal to
In an ellipse $9{x^2} + 5{y^2} = 45$, the distance between the foci is
For the ellipse $\frac{{{x^2}}}{{64}} + \frac{{{y^2}}}{{28}} = 1$, the eccentricity is