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10-2. Parabola, Ellipse, Hyperbola
medium
The equation of the normal at the point $(2, 3)$ on the ellipse $9{x^2} + 16{y^2} = 180$, is
A
$3y = 8x - 10$
B
$3y - 8x + 7 = 0$
C
$8y + 3x + 7 = 0$
D
$3x + 2y + 7 = 0$
Solution
(b) $\frac{{x – {x_1}}}{{{x_1}/{a^2}}} = \frac{{y – {y_1}}}{{{y_1}/{b^2}}}$,
which is the standard equation of normal at point $({x_1},\,{y_1})$.
In the given ellipse, ${a^2} = 20,\,{b^2} = \frac{{180}}{{16}}$.
Hence the equation of normal at the point $(2,\,3)$ is
$\frac{{x – 2}}{{2/20}} = \frac{{y – 3}}{{48/180}}$ ==> $40\,(x – 2) = 15(y – 3)$
==> $8x – 3y = 7$
==> $3y – 8x + 7 = 0$.
Standard 11
Mathematics