Gujarati
10-2. Parabola, Ellipse, Hyperbola
medium

The equation of the normal at the point $(2, 3)$ on the ellipse $9{x^2} + 16{y^2} = 180$, is

A

$3y = 8x - 10$

B

$3y - 8x + 7 = 0$

C

$8y + 3x + 7 = 0$

D

$3x + 2y + 7 = 0$

Solution

(b) $\frac{{x – {x_1}}}{{{x_1}/{a^2}}} = \frac{{y – {y_1}}}{{{y_1}/{b^2}}}$,

which is the standard equation of normal at point $({x_1},\,{y_1})$.

In the given ellipse, ${a^2} = 20,\,{b^2} = \frac{{180}}{{16}}$.

Hence the equation of normal at the point $(2,\,3)$ is

$\frac{{x – 2}}{{2/20}} = \frac{{y – 3}}{{48/180}}$ ==> $40\,(x – 2) = 15(y – 3)$

==> $8x – 3y = 7$

==> $3y – 8x + 7 = 0$.

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.