The equation of the tangent at the point $(a\sec \theta ,\;b\tan \theta )$ of the conic $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$, is
The equation of the tangent at the point $(a\sec \theta ,\;b\tan \theta )$ of the conic $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$, is
- A
$x{\sec ^2}\theta - y{\tan ^2}\theta = 1$
- B
$\frac{x}{a}\sec \theta - \frac{y}{b}\tan \theta = 1$
- C
$\frac{{x + a\sec \theta }}{{{a^2}}} - \frac{{y + b\tan \theta }}{{{b^2}}} = 1$
- D
None of these
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