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10-2. Parabola, Ellipse, Hyperbola
medium
The equations of the tangents of the ellipse $9{x^2} + 16{y^2} = 144$ which passes through the point $(2, 3)$ is
A
$y = 3,\;x + y = 5$
B
$y = - 3,\;x - y = 5$
C
$y = 4,\;x + y = 3$
D
$y = - 4,\;x - y = 3$
Solution
(a) The tangent will be $y – 3 = m(x – 2)$ ==> $y – mx = 3 – 2m.$
But it is tangent to the given ellipse, therefore $m = 0,\, – 1$.
Hence tangents are $y = 3$ and $x + y = 5$.
Standard 11
Mathematics