Escape velocity for a body projected vertically upwards from surface of earth is 11, km/s . If body

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7.Gravitation

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The escape velocity for a body projected vertically upwards from the surface of earth is $11\, km/s$. If the body is projected at an angle of $45^o$ with the vertical, the escape velocity will be ........... $km/s$

A

$22$

B

$11$

C

$\frac{{11}}{{\sqrt 2 }}$

D

$11\sqrt 2 $

Solution

Since escape velocity $\left( {{v_e} = \sqrt {2g{R_e}} } \right)$ independent of angle of projection, so it will not change

Standard 11

Physics

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