Figure gives electric potential V as a function of distance through five regions on x -axis. Which o

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2. Electric Potential and Capacitance

easy

The figure gives the electric potential $V$ as a function of distance through five regions on $x$-axis. Which of the following is true for the electric field $E$ in these regions

${E_1} > {E_2} > {E_3} > {E_4} > {E_5}$

${E_1} = {E_3} = {E_5}$ and ${E_2} < {E_4}$

${E_2} = {E_4} = {E_5}$ and ${E_1} < {E_3}$

${E_1} < {E_2} < {E_3} < {E_4} < {E_5}$

Solution

(b)Electric field in the region $1,\, 3$ and $5$ is zero i.e. ${E_1} = {E_3} = {E_5}$
Slope of the line $BC$ $<$ Slope of the line $DE$
i.e. $ E_2 < E_4$

Standard 12

Physics

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medium

Figure shows two equipotential lines in $x, y$ plane for an electric field. The scales are marked. The $x-$ component $E_x$ and $y$ -component $E_y$ of the electric field in the space between these equipotential lines are respectively :-

medium

The potential gradient is a

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hard

$A, B$ and $C$ are three points in a uniform electric field. The electric potential is

easy

The figure gives the electric potential $V$ as a function of distance through five regions on $x$-axis. Which of the following is true for the electric field $E$ in these regions

Solution

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Electric potential in a region is varying according to the relation $V=\frac{3 x^2}{2}-\frac{y^2}{4}$, where $x$ and $y$ are in metre and $V$ is in volt. Electric field intensity (in $N/C$) at a point $(1 \,m , 2 \,m$ ) is ……

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