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8. Sequences and Series
easy
The first term of an $A.P. $ is $2$ and common difference is $4$. The sum of its $40$ terms will be
A
$3200$
B
$1600$
C
$200$
D
$2800$
Solution
(a) First term $a = 2$ and common difference $d = 4$ and $n = 40$.
Then ${S_n} = \frac{n}{2}[2a + (n – 1)d]$
$ = 20[4 + 39 \times 4] = 20[4 + 156]$
$ = 160 \times 20 = 3200$.
Standard 11
Mathematics