The first term of an infinite geometric progr | vedclass

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Question

(b) $5 = \frac{x}{{1 - r}}$

$ \Rightarrow 5 - 5r = x$

$ \Rightarrow r = 1 - \frac{x}{5}$

As $|r| < 1$

$i.e.$, $\left| {\,1 - \frac{x}{5

Vedclass · Accepted Answer

$0 < x < 10$

Vedclass · Answer

(b) $5 = \frac{x}{{1 - r}}$ $ \Rightarrow 5 - 5r = x$ $ \Rightarrow r = 1 - \frac{x}{5}$ As $|r| < 1$ $i.e.$, $\left| {\,1 - \frac{x}{5}\,} \right| < 1$ $ - 1 < 1 - \frac{x}{5} < 1$ $ - 5 < 5 - x < 5 $ $ - 10 < - x < 0 $ $ 10 > x > 0 $ $ 0 < x < 10$

The first term of an infinite geometric progression is $x$ and its sum is $5$. Then

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