The general solution of {sin ^2}theta sec the | vedclass

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Question

(b) The given equation can be written as

$ \Rightarrow $$\frac{{{{\sin }^2}	heta }}{{\cos 	heta }} + \sqrt 3 	an 	heta = 0$

$ \Rightarrow $

Vedclass · Accepted Answer

$	heta = n\pi ,n \in Z$

Vedclass · Answer

(b) The given equation can be written as

$ \Rightarrow $$\frac{{{{\sin }^2}	heta }}{{\cos 	heta }} + \sqrt 3 	an 	heta = 0$

$ \Rightarrow $ $	an 	heta \sin 	heta + \sqrt 3 	an 	heta = 0$

$	an 	heta (\sin 	heta + \sqrt 3 ) = 0$

$ \Rightarrow $ $	an 	heta = 0$ 

$ \Rightarrow $$	heta = n\pi ,\,n \in Z$.

The general solution of ${\sin ^2}\theta \sec \theta + \sqrt 3 \tan \theta = 0$ is

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