The half-life period of a radio-active elemen | vedclass

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Question

According to question,

Half life of $X, T_{1 / 2}=	au_{	ext {av }},$ average life of $Y$

$\Rightarrow \frac{0.693}{\lambda_{X}}=\frac{1}{\lamb

Vedclass · Accepted Answer

$Y$ will decay faster than $X$

Vedclass · Answer

According to question,

Half life of $X, T_{1 / 2}=	au_{	ext {av }},$ average life of $Y$

$\Rightarrow \frac{0.693}{\lambda_{X}}=\frac{1}{\lambda_{Y}} \Rightarrow \lambda_{X}=(0.693) \cdot \lambda_{Y}$

$	herefore \lambda_{X}<\lambda_{Y}$

Now, the rate of decay is given by

$-\frac{d N}{d t}=\lambda N$

$Y$ will decay faster than $X .[\because N 	ext { is some }]$

The half-life period of a radio-active element $X$ is same as the mean life time of another radio-active element $Y$ Initially they have the same number of atoms. Then

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