The inward and outward electric flux for a closed surface in units of $N{\rm{ - }}{m^2}/C$ are respectively $8 \times {10^3}$ and $4 \times {10^3}.$ Then the total charge inside the surface is [where ${\varepsilon _0} = $ permittivity constant]
The inward and outward electric flux for a closed surface in units of $N{\rm{ - }}{m^2}/C$ are respectively $8 \times {10^3}$ and $4 \times {10^3}.$ Then the total charge inside the surface is [where ${\varepsilon _0} = $ permittivity constant]
- A
$4 \times {10^3}$ $C$
- B
$ - 4 \times {10^3}$ $C$
- C
$\frac{{( - 4 \times {{10}^3})}}{\varepsilon }$ $C$
- D
$ - 4 \times {10^3}{\varepsilon _0}$ $C$
Similar Questions
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$(b)$ the charge within the cube. Assume that $a=0.1 \;m$
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