Gujarati
10-2. Parabola, Ellipse, Hyperbola
medium

The length of the axes of the conic $9{x^2} + 4{y^2} - 6x + 4y + 1 = 0$, are

A

$\frac{1}{2},\;9$

B

$3,\;\frac{2}{5}$

C

$1,\;\frac{2}{3}$

D

$3, \;2$

Solution

(c) Given that, the equation of conic

$9{x^2} + 4{y^2} – 6x + 4y + 1 = 0$

==>${(3x – 1)^2} + {(2y + 1)^2} = 1$

==> $\frac{{{{\left( {x – \frac{1}{3}} \right)}^2}}}{{\frac{1}{9}}} + \frac{{{{(y + 1)}^2}}}{{\frac{1}{2}}} = 1$.

Here $a = \frac{1}{3}$, $b = \frac{1}{2}$;  $2a = \frac{2}{3}$, $2b = 1.$

Length of axes are $\left( {1,\,\frac{2}{3}} \right)$.

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.