The length of the axes of the conic $9{x^2} + 4{y^2} - 6x + 4y + 1 = 0$, are
The length of the axes of the conic $9{x^2} + 4{y^2} - 6x + 4y + 1 = 0$, are
- A
$\frac{1}{2},\;9$
- B
$3,\;\frac{2}{5}$
- C
$1,\;\frac{2}{3}$
- D
$3, \;2$
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