The length of the transverse axis of a hyperbola is $7$ and it passes through the point $(5, -2)$. The equation of the hyperbola is
$\frac{4}{{49}}{x^2} - \frac{{196}}{{51}}{y^2} = 1$
$\frac{{49}}{4}{x^2} - \frac{{51}}{{196}}{y^2} = 1$
$\frac{4}{{49}}{x^2} - \frac{{51}}{{196}}{y^2} = 1$
None of these
A rectangular hyperbola of latus rectum $2$ units passes through $(0, 0)$ and has $(1, 0)$ as its one focus. The other focus lies on the curve -
Curve $xy = {c^2}$ is said to be
If the straight line $x\cos \alpha + y\sin \alpha = p$ be a tangent to the hyperbola $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$, then
Let the eccentricity of the hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ be reciprocal to that of the ellips $x^2+4 y^2=4$. If the hyperbola passes through a focus of the ellipse, then
$(A)$ the equation of the hyperbola is $\frac{x^2}{3}-\frac{y^2}{2}=1$
$(B)$ a focus of the hyperbola is $(2,0)$
$(C)$ the eccentricity of the hyperbola is $\sqrt{\frac{5}{3}}$
$(D)$ the equation of the hyperbola is $x^2-3 y^2=3$
Equation of the normal to the hyperbola $\frac{{{x^2}}}{{25}} - \frac{{{y^2}}}{{16}} = 1$ perpendicular to the line $2x + y = 1$ is