10-2. Parabola, Ellipse, Hyperbola
hard

The locus of the point of intersection of the lines $(\sqrt{3}) kx + ky -4 \sqrt{3}=0$ and $\sqrt{3} x-y-4(\sqrt{3}) k=0$ is a conic, whose eccentricity is .............

A

$0$

B

$2$

C

$4$

D

$8$

(JEE MAIN-2021)

Solution

$K =\frac{4 \sqrt{3}}{\sqrt{3} x + y }=\frac{\sqrt{3} x – y }{4 \sqrt{3}}$

$\Rightarrow 3 x ^{2}- y ^{2}=48$

$\Rightarrow \frac{ x ^{2}}{16}-\frac{ y ^{2}}{48}=1$

Now, $48=16\left( e ^{2}-1\right)$

$\Rightarrow e =\sqrt{4}=2$

Standard 11
Mathematics

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