The magnetic field in a plane electromagnetic wave is given by
${B_y} = \left( {2 \times {{10}^{ - 7}}} \right)\sin \left( {0.5 \times {{10}^3}x + 1.5 \times {{10}^{11}}t} \right)T$
$(a)$ What is the wavelength and frequency of the wave?
$(b)$ Write an expression for the electric field.
$(a)$ Comparing the given equation with
$B_{y}=B_{0} \sin \left[2 \pi\left(\frac{x}{\lambda}+\frac{t}{T}\right)\right]$
We get, $\lambda=\frac{2 \pi}{0.5 \times 10^{3}} m =1.26 \,m$
and $\quad \frac{1}{T}=v=\left(1.5 \times 10^{11}\right) / 2 \pi=23.9 \,GHz$
$(b)$ $E_{0}=B_{0} c=2 \times 10^{-7} \,T \times 3 \times 10^{8} \,m / s =6 \times 10^{1}\, V / m$
The electric field component is perpendicular to the direction of propagation and the direction of magnetic field. Therefore, the electric field component along the $z$ -axis is obtained as
$E_{z}=60 \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} t\right)\, V / m$
A particle of mass $\mathrm{m}$ and charge $\mathrm{q}$ has an initial velocity $\overline{\mathrm{v}}=\mathrm{v}_{0} \hat{\mathrm{j}} .$ If an electric field $\overrightarrow{\mathrm{E}}=\mathrm{E}_{0} \hat{\mathrm{i}}$ and magnetic field $\overrightarrow{\mathrm{B}}=\mathrm{B}_{0} \hat{\mathrm{i}}$ act on the particle, its speed will double after a time:
The magnetic field of a plane electromagnetic wave is given by
$\overrightarrow{ B }=2 \times 10^{-8} \sin \left(0.5 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ j } T$ The amplitude of the electric field would be.
Light with an energy flux of $18 \;W / cm ^{2}$ falls on a nonreflecting surface at normal incidence. If the surface has an area of $20\; cm ^{2},$ find the average force exerted on the surface during a $30$ minute time span.
The ratio of contributions made by the electric field and magnetic fleld components to the intensity of an electromagnetic wave is :
$(c=$ speed of electromagnetic waves)
An electromagnetic wave of frequency $\nu = 3.0\,MHz$ passes from vacuum into a dielectric medium with permitivity $\varepsilon = 4.0$. Then