Magnitudes of vectors vec A,,vec B and vec C are 3, 4 and 5 units respectively. If vec A + vec B = v

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3-1.Vectors

easy

The magnitudes of vectors $\vec A,\,\vec B$ and $\vec C$ are $3, 4$ and $5$ units respectively. If $\vec A + \vec B = \vec C$, the angle between $\vec A$ and $\vec B$ is

A

$\frac{\pi }{2}$

B

${\cos ^{ - 1}}(0.6)$

C

${\tan ^{ - 1}}\left( {\frac{7}{5}} \right)$

D

$\frac{\pi }{4}$

(AIPMT-1988)

Solution

(a) $C = \sqrt {{A^2} + {B^2}} $

=$\sqrt {{3^2} + {4^2}} = 5$

$\therefore $ Angle between $\overrightarrow A $ and $\overrightarrow B $ is $\frac{\pi }{2}$

Standard 11

Physics

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