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13.Statistics
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The mean and $S.D.$ of $1, 2, 3, 4, 5, 6$ is
A
$\frac{7}{2},\,\sqrt {\frac{{35}}{{12}}} $
B
$3, 3$
C
$\frac{7}{2},\,\sqrt 3 $
D
$3,\,\frac{{35}}{{12}}$
Solution
(a) Mean $\bar x = \frac{{1 + 2 + 3 + 4 + 5 + 6}}{6}$
$ = \frac{{21}}{6} = \frac{7}{2}$
$S.D.$ $ = \sigma = \sqrt {\frac{1}{n}\Sigma x_i^2 – {{(\bar x)}^2}} $
$ = \sqrt {\frac{1}{6}(1 + 4 + 9 + 16 + 25 + 36) – \frac{{49}}{4}} $
$ = \sqrt {\frac{{91}}{6} – \frac{{49}}{4}} $
$ = \sqrt {\frac{{182 – 147}}{{12}}} $
$ = \sqrt {\frac{{35}}{{12}}} $.
Standard 11
Mathematics
Similar Questions
The following values are calculated in respect of heights and weights of the students of a section of Class $\mathrm{XI}:$
Height | Weight | |
Mean | $162.6\,cm$ | $52.36\,kg$ |
Variance | $127.69\,c{m^2}$ | $23.1361\,k{g^2}$ |
Can we say that the weights show greater variation than the heights?
medium