Negation of $p \wedge( q \wedge \sim( p \wedge q ))$ is
$\sim(p \vee q)$
$p \vee q$
$(\sim(p \wedge q)) \wedge q$
$(\sim(p \wedge q)) \vee p$
The inverse of the proposition $(p\; \wedge \sim q) \Rightarrow r$ is
$(p\rightarrow q) \leftrightarrow (q \vee ~ p)$ is
The negation of the statement $(( A \wedge( B \vee C )) \Rightarrow( A \vee B )) \Rightarrow A$ is
Let $p, q, r$ denote arbitrary statements. Then the logically equivalent of the statement $p\Rightarrow (q\vee r)$ is
The statement $( p \wedge q ) \Rightarrow( p \wedge r )$ is equivalent to.