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Basic of Logarithms
easy
The number ${\log _{20}}3$ lies in
A
$\left( {1/4,\,\,1/3} \right)$
B
$\left( {1/3,\,\,1/2} \right)$
C
$\left( {1/2,\,3/4} \right)$
D
$\left( {3/4,\,\,4/5} \right)$
Solution
(b) ${20^{1/3}} < 3 < {20^{1/2}}$$ \Rightarrow $${1 \over 3} < {\log _{20}}3 < {1 \over 2}$
$\therefore {\log _{20}}3 \in \left( {{1 \over 3},\,{1 \over 2}} \right)$.
Standard 11
Mathematics