Basic of Logarithms
easy

The number ${\log _{20}}3$  lies in

A

$\left( {1/4,\,\,1/3} \right)$

B

$\left( {1/3,\,\,1/2} \right)$

C

$\left( {1/2,\,3/4} \right)$

D

$\left( {3/4,\,\,4/5} \right)$

Solution

(b) ${20^{1/3}} < 3 < {20^{1/2}}$$ \Rightarrow $${1 \over 3} < {\log _{20}}3 < {1 \over 2}$

$\therefore {\log _{20}}3 \in \left( {{1 \over 3},\,{1 \over 2}} \right)$.

Standard 11
Mathematics

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