The number ${\log _{20}}3$ lies in
$\left( {1/4,\,\,1/3} \right)$
$\left( {1/3,\,\,1/2} \right)$
$\left( {1/2,\,3/4} \right)$
$\left( {3/4,\,\,4/5} \right)$
If $x = {\log _a}(bc),y = {\log _b}(ca),z = {\log _c}(ab),$then which of the following is equal to $1$
If $\log x:\log y:\log z = (y - z)\,:\,(z - x):(x - y)$ then
Let $a=3 \sqrt{2}$ and $b=\frac{1}{5^{\frac{1}{6}} \sqrt{6}}$. If $x, y \in R$ are such that $3 x+2 y=\log _a(18)^{\frac{5}{4}} \text { and }$ $2 x-y=\log _b(\sqrt{1080}),$ then $4 x+5 y$ is equal to. . . .
If ${\log _{0.3}}(x - 1) < {\log _{0.09}}(x - 1),$ then $x$ lies in the interval
If ${\log _{12}}27 = a,$ then ${\log _6}16 = $