Trigonometrical Equations
hard

अंतराल $\left[\begin{array}{lll}0, & 2 \pi\end{array}\right]$ में समीकरण $|\cot x|=\cot x+\frac{1}{\sin x}$ के हलों की संख्या है

A

$1$

B

$2$

C

$3$

D

$4$

(JEE MAIN-2021)

Solution

If $\cot x>0 \Rightarrow \frac{1}{\sin x}=0$ (Not possible)

If $\operatorname{cotx}<0 \Rightarrow 2 \cot x+\frac{1}{\sin x}=0$

$\Rightarrow 2 \cos x=-1$

$\Rightarrow x =\frac{2 \pi}{3}$ or $\frac{4 \pi}{3}( reject )$

Standard 11
Mathematics

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