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14.Probability
medium
The probabilities of occurrence of two events are respectively $0.21$ and $0.49$. The probability that both occurs simultaneously is $0.16$. Then the probability that none of the two occurs is
A
$0.3$
B
$0.46$
C
$0.14$
D
None of these
Solution
(b) $P(A \cup B) = P(A) + P(B) – P(A \cap B)$
$ = 0.21 + 0.49 – 0.16 \Rightarrow P(A \cup B) = 0.54$
Probability of none of two occurs
$ = 1 – P(A \cup B) = 1 – 0.54 = 0.46.$
Standard 11
Mathematics