The probabilities of occurrence of two events | vedclass

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Question

(b) $P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$ = 0.21 + 0.49 - 0.16 \Rightarrow P(A \cup B) = 0.54$

Probability of none of two occurs

$ = 1

Vedclass · Accepted Answer

$0.46$

Vedclass · Answer

(b) $P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$ = 0.21 + 0.49 - 0.16 \Rightarrow P(A \cup B) = 0.54$

Probability of none of two occurs

$ = 1 - P(A \cup B) = 1 - 0.54 = 0.46.$

The probabilities of occurrence of two events are respectively $0.21$ and $0.49$. The probability that both occurs simultaneously is $0.16$. Then the probability that none of the two occurs is

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