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14.Probability
medium
One card is drawn randomly from a pack of $52$ cards, then the probability that it is a king or spade is
A
$\frac{1}{{26}}$
B
$\frac{3}{{26}}$
C
$\frac{4}{{13}}$
D
$\frac{3}{{13}}$
Solution
(c) Probability of king $P(A) = \frac{4}{{52}} = \frac{1}{{13}}$
Probability of spade $ = \frac{{13}}{{52}}$ $ = \frac{1}{4}$
$\therefore$ $P$ (King or spade) $= P($king) $+ P$ (spade) $ – P$(King and spade)
$ = \frac{1}{{13}} + \frac{1}{4} – \frac{1}{{52}}$
$ = \frac{{4 + 13 – 1}}{{52}} = \frac{{16}}{{52}} = \frac{4}{{13}}$.
Standard 11
Mathematics
Similar Questions
Fill in the blanks in following table :
| $P(A)$ | $P(B)$ | $P(A \cap B)$ | $P (A \cup B)$ |
| $0.5$ | $0.35$ | ……… | $0.7$ |
easy
