One card is drawn randomly from a pack of 52 | vedclass

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Question

(c) Probability of king $P(A) = \frac{4}{{52}} = \frac{1}{{13}}$

Probability of spade $ = \frac{{13}}{{52}}$ $ = \frac{1}{4}$

$	herefore$

Vedclass · Accepted Answer

$\frac{4}{{13}}$

Vedclass · Answer

(c) Probability of king $P(A) = \frac{4}{{52}} = \frac{1}{{13}}$

Probability of spade $ = \frac{{13}}{{52}}$ $ = \frac{1}{4}$

$	herefore$ $P$ (King or spade) $= P($king) $+ P$ (spade) $ - P$(King and spade)

$ = \frac{1}{{13}} + \frac{1}{4} - \frac{1}{{52}}$

$ = \frac{{4 + 13 - 1}}{{52}} = \frac{{16}}{{52}} = \frac{4}{{13}}$.

One card is drawn randomly from a pack of $52$ cards, then the probability that it is a king or spade is

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