In a hostel, $60 \%$ of the students read Hindi newspaper, $40 \%$ read English newspaper and $20 \%$ read both Hindi and English newspapers. A student is selected at random Find the probability that she reads neither Hindi nor English newspapers.

Vedclass pdf generator app on play store
Vedclass iOS app on app store

Let $H$ denote the students who read Hindi newspaper and $E$ denote the students who read English newspaper.

It is given that, $\mathrm P(H)=60 \%=\frac{60}{100}=\frac{3}{5}$

$\mathrm{P}(\mathrm{E})=40 \%=\frac{40}{100}=\frac{2}{5}$

$P(H \cap E)=20 \%=\frac{20}{100}=\frac{1}{5}$

Probability that a student reads Hindi and English newspaper is,

$\mathrm{P}(\mathrm{H} \cup \mathrm{E})^{\prime}=1-\mathrm{P}(\mathrm{H} \cup \mathrm{E})$

$=1-\{\mathrm{P}(\mathrm{H})+\mathrm{P}(\mathrm{E})-\mathrm{P}(\mathrm{H} \cap \mathrm{E})\}$

$=1-\left(\frac{3}{5}+\frac{2}{5}-\frac{1}{5}\right)$

$=1-\frac{4}{5}$

$=\frac{1}{5}$

Similar Questions

If the odds in favour of an event be $3 : 5$, then the probability of non-occurrence of the event is

The probability of solving a question by three students are $\frac{1}{2},\,\,\frac{1}{4},\,\,\frac{1}{6}$ respectively. Probability of question is being solved will be

Fill in the blanks in following table :

$P(A)$ $P(B)$ $P(A \cap B)$ $P (A \cup B)$
$0.35$  ........... $0.25$  $0.6$

An unbiased coin is tossed. If the outcome is a head then a pair of unbiased dice is rolled and the sum of the numbers obtained on the is noted. If the toss of the coin results in tail then a card from a well-shuffled pack of nine cards numbered $1, 2, 3,….., 9$ is randomly picked and the number on the card is noted. The probability that the noted number is either $7$ or $8$ is

  • [JEE MAIN 2019]

If $A$ and $B$ are two events such that $P(A) = \frac{1}{2}$ and $P(B) = \frac{2}{3},$ then