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8. Sequences and Series
easy
श्रेणी $(32)(32) 1/6(32)1/36 ...... $ अनन्त पदों तक का गुणनफल है
A
$16$
B
$32$
C
$64$
D
$0$
Solution
(c) $(32)(32)1/6(32)1/36……$$\infty $
= ${(32)^{1 + \frac{1}{6} + \frac{1}{{36}} + …..\infty }}$
$ = {(32)^{\frac{1}{{1 – (1/6)}}}}$
$ = {(32)^{\frac{1}{{5/6}}}} = {(32)^{6/5}}$
$ = {2^6} = 64$.
Standard 11
Mathematics