Gujarati
8. Sequences and Series
easy

श्रेणी $(32)(32) 1/6(32)1/36 ...... $ अनन्त पदों तक का गुणनफल है

A

$16$

B

$32$

C

$64$

D

$0$

Solution

(c) $(32)(32)1/6(32)1/36……$$\infty $

= ${(32)^{1 + \frac{1}{6} + \frac{1}{{36}} + …..\infty }}$

$ = {(32)^{\frac{1}{{1 – (1/6)}}}}$

$ = {(32)^{\frac{1}{{5/6}}}} = {(32)^{6/5}}$

$ = {2^6} = 64$.

Standard 11
Mathematics

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