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7.Binomial Theorem
medium
The ratio of the coefficient of the middle term in the expansion of $(1+x)^{20}$ and the sum of the coefficients of two middle terms in expansion of $(1+x)^{19}$ is $....$
A
$5$
B
$4$
C
$1$
D
$11$
(JEE MAIN-2021)
Solution
Coeff. of middle term in $(1+x)^{20}={ }^{20} C_{10}$
Sum of Coeff. of two middle terms in
$(1+x)^{19}={ }^{19} C_{9}+{ }^{19} C_{10}$
So required ratio $=\frac{{ }^{20} \mathrm{C}_{10}}{{ }^{19} \mathrm{C}_{9}+{ }^{19} \mathrm{C}_{10}} \frac{{ }^{20} \mathrm{C}_{10}}{{ }^{19} \mathrm{C}_{9}+{ }^{19} \mathrm{C}_{10}}=\frac{{ }^{20} \mathrm{C}_{10}}{{ }^{20} \mathrm{C}_{10}}=1$
Standard 11
Mathematics