Gujarati
1. Electric Charges and Fields
easy

The ratio of the forces between two small spheres with constant charge $(a)$ in air $(b)$ in a medium of dielectric constant $K$ is

A

$1 : K$

B

$K : 1$

C

$1:{K^2}$

D

${K^2}:1$

Solution

(b) ${F_a} = \frac{{{q_1}{q_2}}}{{4\pi {\varepsilon _0}{r^2}}},\,{F_b} = \frac{{{q_1}{q_2}}}{{K4\pi {\varepsilon _0}{r^2}}}$ ==> ${F_a}:{F_b} = K:1$

Standard 12
Physics

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