Basic of Logarithms
normal

The rationalising factor of $2\sqrt 3 - \sqrt 7 $ is

A

$\sqrt 3 + \sqrt 7 $

B

$2\sqrt 3 + \sqrt 7 $

C

$\sqrt 3 + 2\sqrt 7 $

D

None of these

Solution

(b) $(2\sqrt 3 – \sqrt 7 )\,(2\sqrt 3 + \sqrt 7 ) = 12 – 7 = 5$ (a rational)

$\therefore$ Rationalising factor  $=2\sqrt 3 + \sqrt 7 $

Standard 11
Mathematics

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