1.Relation and Function
easy

The relation $R$ defined in $N$ as $aRb \Leftrightarrow b$ is divisible by $a$ is

A

Reflexive but not symmetric

B

Symmetric but not transitive

C

Symmetric and transitive

D

None of these

Solution

(a) For any $a \in N$, we find that $a|a$, therefore $R$ is reflexive but $R$ is not transitive, because $aRb$ does not imply that $bRa$.

Standard 12
Mathematics

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