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Trigonometrical Equations
hard
સમીકરણ $\frac{{\tan 3x - \tan 2x}}{{1 + \tan 3x\tan 2x}} = 1$ નું સમાધાન કરે તેવી $x$ ની કિમતોનો ગણ મેળવો.
A
$\phi $
B
$\frac{\pi }{4}$
C
$\left\{ {n\pi + \frac{\pi }{4}:n = 1,\,2,\,3.....} \right\}$
D
$\left\{ {2n\pi + \frac{\pi }{4}:n = 1,\,2,\,3.....} \right\}$
Solution
(a) $\tan (3x – 2x) = \tan x = 1$ ==> $x = n\pi + \frac{\pi }{4}$
But this value does not satisfy the given equation.
Hence option $(a)$ is the correct answer.
Standard 11
Mathematics
