Gujarati
Hindi
8. Sequences and Series
hard

The sides of a triangle are distinct positive integers in an arithmetic progression. If the smallest side is $10$, the number of such triangles is

A

$8$

B

$9$

C

$10$

D

infinitely many

(KVPY-2012)

Solution

(b)

Let the sides be $a, b, c$ which are in A.P. with $c$ as the smallest.

$\therefore c =10$

$\therefore a , b > 10$

$\therefore 2 b = a + c = a +10$

$\therefore b + c > a$

$\Rightarrow b +10 > a$

From eq $(1)$ and $(2)$:

$\Rightarrow b +10 > 2 b -10$

$\Rightarrow b < 20$

$\therefore 10 < b < 20$

$\therefore$ No. of possible values of $b=9$

$\therefore$ No. of triangles possible $=9$

Standard 11
Mathematics

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