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8. Sequences and Series
hard
The sides of a triangle are distinct positive integers in an arithmetic progression. If the smallest side is $10$, the number of such triangles is
A
$8$
B
$9$
C
$10$
D
infinitely many
(KVPY-2012)
Solution
(b)
Let the sides be $a, b, c$ which are in A.P. with $c$ as the smallest.
$\therefore c =10$
$\therefore a , b > 10$
$\therefore 2 b = a + c = a +10$
$\therefore b + c > a$
$\Rightarrow b +10 > a$
From eq $(1)$ and $(2)$:
$\Rightarrow b +10 > 2 b -10$
$\Rightarrow b < 20$
$\therefore 10 < b < 20$
$\therefore$ No. of possible values of $b=9$
$\therefore$ No. of triangles possible $=9$
Standard 11
Mathematics